1) (√5+2)²-4√5=9
5+4√5+4-4√5=9
5+4=9
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2)Aduci la acelasi numitor
2-√3(√3-1)=√3-1
2-3+√3=√3-1
2-3=-1
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4.)Logaritmii au aceiasi baza,poti sa delogaritmezi.
x²+8=6x
x²-6x+8=0
x1=3-√(9-8)=3-√1=2 x2=3+1=4
x1=2 , x2=4
7)Ridici la patrat ambii membrii
9+12√2+8-(9-6√8+8)=17+12√2-17-12√2=0
10Ai aceiasi baza, delogaritmezi
x²+1=1 => x²=0 => x=0
15)og [11]11=1
log[1/7]7= -1
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log[11]11+log[1/7]7=1-1=0
