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Va rog repede!!!!!!! Aflati pe x 2 spura x+3=x+3 supra 8 repedeee

Răspuns :

[tex] \frac{2}{x+3} = \frac{x+3}{8} \\ [/tex]

(x+3)²=2*8
x²+6x+9=16
x²+6x+9-16=0
x²+6x-7=0
Δ=b²-4ac=6²+4*7=36+28=64=8²
x1,2=[tex] \frac{-b+ \sqrt{Δ} }{2a} \\
 x1= \frac{-6+8}{2} = \frac{2}{2} =1 \\
x2= \frac{-6-8}{2} = \frac{-14}{2} =-7[/tex]