Aria unui trapez este [tex] \frac{(B + b)h}{2} [/tex] , unde B e baza mare, b e baza mica, iar h e inaltimea.
Inlocuind valorile tale, A = [tex] \frac{(7-2 \sqrt{3}+6-3 \sqrt{3})(13+5 \sqrt{3}) }{2} [/tex] = [tex] \frac{(13-5 \sqrt{3} )(13+5 \sqrt{3}) }{2} [/tex] = [tex] \frac{169-125}{2} [/tex] = [tex] \frac{44}{2} [/tex] = 22
