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aratati ca numarul 2018 la puterea 2 minus 2018 minus 2017 este pătrat perfect

Răspuns :

2018²-2018-2017=
=2018×(2018-1)-2017
=2018×2017-2017=
=2017×(2018-1)=
=2017×2017=
=2017²
2018 ^ 2-(2018-2017)
2018^2-1
2018^2-2018^0
2018^2-0=2018^2