Na+ HCl---> NaCl +1/2H2.......................ORI a moli
Zn +2HCl--> ZnCl2 +H2..........................ORI b moli
bilantul masei de metale:
8,8g= a,molx23g/mol+ b,molx 65g/mol
bilantul moli de H2
(a/2+b)= 3,36l/22,4l/mol--> (a/2+b)=0,15
din cele doua ecuatii--> a=b=0,1mol
in 8,8g amestec metale.....o,1x23gNa........0,1x65gZn
100g.....................................x..........................y...................calculeaza !!!!
bilantul masei de HCl
m,HCl= (a+2b)molx36,5g/mol= 10,95g
10,95g=md, masa dizolvata in solutie c=mdx100/ms
36,5/100= 10,95/ ms---------------->ms=----------------------calculeaza !!!!
