c) ro=ms/Vs => ms=ro*Vs=1,3075*153=200g sol
C=md/ms*100=80/200*100=40℅
d) C1=md1/ms1*100=>md1=C*ms1/100=94*200/100=188g alcool
C2=md2/ms2*100=>md2=C2*ms2/100=40*400/100=160g
md final = md1+md2=188+160=348g alcool
ms final = ms1+ms2=200+400=600g sol alcool
Cfinal=mdf/msf*100=348/600*100=58℅
2. a) C=md/ms*100=>md=C*ms/100=5*80/100=4g H2SO4
b) ro=ms/Vs => ms=ro*Vs=1,844*50=92,2g sol H2SO4
C=md/ms*100=>md=C*ms/100=98*92,2/200=90,356g H2SO4
3. a) C=md/ms*100=>ms=md*100/C=40*100/25=160g sol
b) C*mH2O=md(100-C) => md=C*mH2O/100-C = 20*200/100-20=50g
ms=md+mH2O=50+200=250g sol
4. C*mH2O=md(100-C) => md=C*mH2O/100-C=25*6/100-25=2kg alcool etilic