1.4b+6=14
4b=8
B=2 lei
2.total 540 calc in 3 zile
A prima zi b a 2 a c a 3a zi
B=2×a
C=3×b dar b=2×a c = 3x2a=6a
A+b+c=540
A+2a+6a=540
9a=540
a=60 calc in prima zi
B=2×60=120 calc in a 2 a zi
C=3×120=360 calc in a 3 a zi
Verif 60+120+360=540
540=540 adevarat
3)dist totala 510
A b c nr de zile
A=2×b
C=a+b+24=2b+b+24=3b+24
A+b+c=510
2b+b+3b+24=510
6b+24=510
B+4=85
B=81
A=2×81=162
C=3b+24=3*81+24=243+24=267 km
Verificare
81+162+267=510
510=510 adevarat
Atentie la problema asta sigur ai gresit enuntul altfel nu are logica.am considerat ca in cea de a 2 a zi a parcurs de 2 ori mai putin decat in prima zi