a) CH2-CH=CH-CH2 , 2-butena
b) H2C=CH2 + H2O --H2SO4--> CH3-CH2-OH
3C4H8 + 4K2Cr2O7 + 16H2SO4 -> 6CH3-COOH + 4K2SO4 + 4Cr2(SO4)3 + 16H2O
C⁻¹ -4e⁻ => C⁺³ ||6||3
C⁻¹ -4e⁻ => C⁺³ ||6||3
Cr₂⁺⁶ => Cr₂⁺³ |8||4
c) n=V/Vm= 0,7392/22,4=0,033 moli alchena
3 moli C4H8......................4 moli K2Cr2O7
0,033 moli.........................x=0,044 moli K2Cr2O7
Cm=n/Vs => Vs=n/Cm = 0,044/1,25 = 0,0352L .. Nu sunt sigur si nu inteleg notatia de la c) cu L (-1) ??