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suma a 3 nr consecutive este 29

Răspuns :

a+b+c =39 =>............=segment
a,b,c=consecutive
a,b,c=?
a............
b.............+1
c..............+1+1
39-(1+1+1)=36(3segmente egale)
36:3=12(un segment
a=12
b=13
c=14
sper ca te-am ajutat