100mL vin...........12 mL alcool
1000mL..............x=120mL alcool
m alcool = 120*0,8=96g
C2H5-OH + O2 => CH3-COOH + H2O
46g alcool..........60g acid
96g alcool..........x=125,217g acid (m pur)
m impur = 125,217*100/90=139,13g acid
mp = 75*139,13/100=104,34g acid