d( M,AB)=d(M, AC)=d(M.AD)=MA=5
D( M, CD)= MP, unde P∈CD, asa fel incatAP⊥CD (teorema celor 3 perpendiculare)
deci MP=inlatimea coresp ipotenuzei in tr.dr ACD= AC*AD/CD
=6*8/ √6²+8²=6*8/10=4.8
MP²=MA²+MP²=5²+4,8²=48,04
MP=√48,04=(√4804)/10= (2√1201)/10=(√1201)/5