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f:R->R, f(x)=2x+1, g(x)=3x-1, h(x)=4x.
Det. f compus cu g compus h.


Răspuns :

(f○g○h)(x) = [(f○g)○h](x); f(g(x)) = 2•(3x - 1) +1 = 6x - 2 + 1 = 6x -1; (f○g)[h(x)] = 6•(4x) - 1 = 24x - 1