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ex 3 varooog repeeede

Ex 3 Varooog Repeeede class=

Răspuns :

a+b+c=639 

a+(a+1)+(a+1+1)=639
1+1+1=3
639-3=636
636:3=212(a)
212+1=213(a+1)\ (b)
212+1+1=214(a+1+1)\(c)

verificare : 212+213+214=639
si sunt si nr consecutive 

PS: si eu am aceias culegere 

639:3=213
Nr sunt 212,213,214