1. MC2H4 = 28g/mol
28g C2H4...........................1389 Kj
12,5g C2H4...........................x = 620 KJ
2. C4H10 + 13/2O2 -> 4CO2 + 5H2O + Q
3. Q=m*C*Δt = 50*4,18*60 = 12540 KJ
1kg huila.........................36500 KJ
x kg................................12540 KJ
x=0,343 kg huila