notam:...caciulite=>a caciulite 2...=> a) |___|___|
fulare =>b fulare 2 => b) |___|___|_|___|___|_|
camasi =>c camasi 2 => c) |___|___|_|___|___|___|_|___|
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2a+2b+2c=140 lei. 12 caciulite (segmenti)+(5*4)= 140 lei
b=2a+5
c=b+a
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a=?b=?c=?
2a+((2a+5)*2)+(((2a+5)*2)+(a*2))=140 lei
2a+(4a+10)+(4a+10)+2a=140lei
12a+20=140 lei
12a=140-20
12a=120 lei
a=120:12
a=10 lei...........=> 1 caciulita =10 lei....=>2 caciulite =10*2=20 lei
b=2*10+5
b=25 lei .............=>1 fular =25 lei........=>2 fulare =25*2=50 lei
c=25+10
c=35 lei...............=>1 camasa =35 lei...=>2 camasi =35*2=70 lei
a+b+c=140 lei
20+50+70=140 lei
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sau
1fular=2 caciulite+5
1camasa=1fular+1caciulita
am obtinut 12 segmanti si de 4 ori 5 lei.....=> 4*5=20
Aflam cat costa o caciulita si apoi cat costa 2 caciulite
140-20=120 lei (20 caciulite)=>
120:12=10 lei costa o caciulita
10*2=20 lei costa 2 caciulite
Aflam cat costa un fular si apoi cat costa 2 fulare
stim ca 1 fular=2caciulite +5.=>
10*2=20 lei 2 caciulite
20+5=25 lei costa un fular
25*2=50 lei costa 2 fulare
Aflam cat costa o camasa si apoi cat costa 2 camasi
stim ca o camasa = 1fular +1 caciulita...=>
25+10= 35 lei costa o camasa.
35*2=70 lei costa 2 camasi
verificare
20+50+70=140 lei
