0,1mol Niu (v)
Zn +CuSO4=ZnSO4+Cu
1mol
1)v(Zn) dupa formula
v(Zn)=m(Zn)/M(Zn)=6,5g/65g/mol=0,1mol
2)v(ZnSO4)dupa ecuatia reactiilor
v(ZnSO4)/1mol=0,1mol/1mol
v(ZnSO4)=0,1*1mol/1mol=0,1mol
3)m(ZnSO4)dupa formula
m(ZnSO4)=v(ZnSO4)*M(ZnSO4)=0,1mol*161g/mol=16,1g
Raspuns:m(ZnSO4)=16,1g
v(ZnSO4)=0,1mol