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Prelucrez fiecare radical:
[tex]\it \sqrt8 = \sqrt{4\cdot2} =2\sqrt2
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\sqrt{32} = \sqrt{16\cdot2} = 4\sqrt2
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\sqrt{50} = \sqrt{25\cdot2} = 5\sqrt2
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\sqrt{18}=\sqrt{9\cdot2} = 3\sqrt2
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Acum,\ \ avem:
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6\cdot2\sqrt2-3\cdot4\sqrt2+9\cdot5\sqrt2+5\cdot3\sqrt2=
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=12\sqrt2-12\sqrt2+45\sqrt2+15\sqrt2 =60\sqrt2.[/tex]
La final, am redus primii 2 termeni (opuși !).
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