ecuatia reactiei:
2CnH2n+2 O----->CnH2n+1-O-H2n+1Cn + H2O
M,alcool= [12n,gC+(2n+2)gH+16gO]= 14n+18 g/mol
M,eter=[2x12n,gC+2(2n+1)gH+16g0]=28n+18 g/mol
2X(14n+18).g...............28n+18g
13,8.g..............................11,1g
2x11( 14n+18)=13,8(28n+18)--------------------------> calculeaza, afla n si formula alcoolului si eterului !!!!!!!