Vs1=200ml deoarece 1ml=1cmcub
ms1=roxV..>m1=200mlx1,11g/ml
c1=22%
c1= md1x100/ms1---> md1= 22x200x1,11/100=48,84g
md2=md1=48,84g
c2=10%
10= 48,84x100/ms2----> ms2=488,4g
comparand ms2=488,4g ,masa la care trebuie sa ajungem,cu ms1= 222g,
rezulta ca masa de apa ce trebuie adaugata ,la prima solutie este
m,apa= 488,4-222 g