[tex] a^{2}- b^{2} = 40 [/tex]
(a+b)(a-b)=40
10(a-b)=40 => a-b=40/10=4
Fac sistem si obtin : [tex] \left \{ {{a+b=10} \atop {a-b=4}} \right. [/tex]
Adun ecuatiile si obtin ca:
2a=14=>a=7
a+b=10=>b=10-a=10-7=3
Asadar [tex] \left \{ {a=7} \atop {b=3}} \right. [/tex]