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√0,(3) = √(3/9) = √3/3
√0,(2) = √(2/9) = √2/3
4/(3√2) =(4√2)/3·2= 2√2/3
Acum, expresia devine:
[tex]\it \left(\dfrac{\sqrt3}{3} + \dfrac{2\sqrt3}{3}\right)\cdot\sqrt3 +\left(\dfrac{\sqrt2}{3}+\dfrac{2\sqrt2}{3}\right)\cdot\sqrt2 = \dfrac{3\sqrt3}{3}\cdot\sqrt3+\dfrac{3\sqrt2}{3}\cdot\sqrt2
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=\sqrt3\cdot\sqrt3 +\sqrt2\cdot\sqrt2 = 3+2=5[/tex]
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