[tex]21\frac{1}{5}:(7\frac{1}{5}-3\frac{1}{10}+6\frac{1}{2})+\frac{2}{3}\cdot(\frac{5}{2}-\frac{5}{9}):\frac{1}{27}=\\
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=\frac{106}{5}(\frac{72-31+65}{10})+\frac{2}{3}(\frac{45-10}{18})\cdot27=\\
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=\frac{106}{5}\cdot\frac{106}{10}+35=\frac{106^2+1750}{50}=\frac{12986}{50}=259,72[/tex]
