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Calculati : √1+3²+√36 + √2·0,5+2 +3 ·√17pe9

Răspuns :

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[tex]\it \sqrt1+3^2+\sqrt{36} +\sqrt{2\cdot0,5}+2+3\cdot\sqrt{1\dfrac{7}{9}}=1+9+6+\sqrt1+2+ \\\;\\ +3\cdot\sqrt{\dfrac{16}{9}} =19+3\cdot\dfrac{4}{3} =19+4=23.[/tex]

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