6HCl+2Al=2Al[tex] Cl_{3} [/tex] + 3[tex] H_{2} [/tex]
ν(Al)=m(Al)/M(Al)=10,8/27=0.4 mol
Aflam ν(HCl):
0,4/2=x/6
x=0,4*6/2=1,2 mol
ν(HCl)=2,1 mol
m(HCl)=M(HCl)*ν(HCl)=1,2*36=43,29g
Aflam ν([tex]H_{2} [/tex] ):
0,4/2=x/3
x=0,4*3/2=0,6 mol
Aflam masa Hidrogenului:
m(H2)=M(H2) *ν([tex]H_{2} [/tex]) =0,6*2=1,2 g