ro=ms/V => ms=ro*V = 0,8*200 = 160g sol CH3-COOH
C=md/ms*100 => md = 144g acid acetic
n=m/M= 144/60 = 2,4 moli acid
3C2H5-OH + 2K2Cr2O7 + 8H2SO4 => 3CH3-COOH + 2K2SO4 + 2Cr2(SO4)3 + 11H2O
C(-1) -4e => C(+3) ||6||3
Cr2(+6) +6e => Cr2 (+3) ||4|2
2 moli K2Cr2O7...........................3 moli acid
x moli K2Cr2O7...........................2,4 moli acid
x=1,6 moli K2Cr2O7
Cm=n/Vs => Vs= 16 L K2Cr2O7