n=V/Vm=1120/22,4 = 50 moli C2H2
CaC2 + 2H2O => C2H2 + Ca(OH)2
a) 64g CaC2.........................1 mol C2H2
x g........................................50 moli C2H2
x=64*50 = 3200g = 3,2 kg CaC2
p=mp/mimp*100 = 3,2/4*100 = 80 %
b) C2H2 + HCl => CH2=CH-Cl
nC2H2=nC2H3Cl = 50 moli
m C2H3Cl = 50*62,5 = 3125g C2H3Cl (mt)
n(eta) = mp/mt*100 => mp=n*mt/100 = 90*3125/100 = 2812,5g C2H3Cl
c) nC2H2 = nHCl = 50 moli
Cm=n/Vs => Vs=n/Cm = 50/5 = 10 L sol HCl