Al2O3 + 3 H2SO4 = Al2(SO4)3 + 3 H2O
MAl2O3=2*27+3*16=102
MH2SO4=2*1+32+4*16=98
MAl2(SO4)3 = 2*27+(32+4*16)*3=342
102 g Al2O3 ................ 3*98 g H2SO4 ................... 342 g Al2(SO4)3
x ................ 160 g H2SO4 ................... y
x=(102*160)/(3*98)=55,5 g Al2O3
y=(160*342)/(3*98)=186,12 g Al2(SO4)3