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[tex]( \frac{4}{radical din 50} + \frac{3}{radical din 18} - \frac{1}{radical din 32} ) [/tex] × [tex] \sqrt{2} [/tex]

Dau coronita!!!!


Răspuns :

(4/5√2+3/3√2-1/4√2)x√2=
=4/5+1-1/4=
=(16+20-5)/20=
=31/20

O seara buna!
[tex]( \frac{4}{ \sqrt{50} } + \frac{3}{ \sqrt{18} } - \frac{1}{ \sqrt{32} })* \sqrt{2} = \\ \frac{4}{ \sqrt{50} }*\sqrt{2}+\frac{3}{ \sqrt{18} }*\sqrt{2}-\frac{1}{ \sqrt{32} }*\sqrt{2}= \\ \frac{4}{5} +1- \frac{1}{4}= \frac{16+20-5}{20} = \frac{31}{20} [/tex]

/robèrtinni