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rezolvati in multimea numerelor naturale a ecuatile. 5(2x-1)+17=52. 125-3(2x-1)=98

Răspuns :

5(2x-1)+17=52
10x-5+17=52
10x=52+5-17
10x=40
x=40/10
x=4 € N
125-3(2x-1)=98
125-(6x-3)=98
125-6x+3=98
-6x=98-125-3
-6x=-30 |:(-6)
x=5 € N
10x-5+17=52
10x=52-17+5
10x=40
x=4

125-6x+3=98
125+3-98=6x
30=6x
x=5