M,HCl=(1gH+35,5gCl)/mol= 36,5g/mol
M,MgCl=(24gMg+35,5gCl)/mol= 59,5g/mol
ecuatia reactiei este:
2mol.....................1mol 1mol
Mg + 2HCl---------------> MgCl2 + H2↑
2x36,5g...............59,5g.........2g
24g............................x............y
calculeaza x,y !!!!