👤

suma a trei nr consecutive este387

Răspuns :

387/3=129 
129-1=128
129+1=130

nr sunt: 128, 129, 130
a+b+c=387
b=a+1
c=a+2
a+a+1+a+2= 387
3a+3 =387
3a=387-3
3a =384
a=384:3
a=128
b=128+1=129
c=128+2=130