T·OB=Fe1·OA
dar OB=2OA pt ca OB=AB
T=Fe2/2=G2/2=m2g/2
Fe1=G1=m1g
rezulta ca m2g/2·2OA=m1g·OA⇒m1/m2=1 masele sunt egale
b)m1=m2=m=20kg
Fe1=G1=m1g=20kgx10N/kg=200N
Fe2=G2=m2g=20kgx10N/kg=200N
c)Fe1=k1Δl1⇒Δl1=Fe1/k1=200N/500N/m=0,4m
Fe2=k2Δl1=2k1Δl1⇒Δl1=Fe1/2k1=200N/1000N/m=0,2m