n = numarul cel mai mare , astfel ca :
n : 5 = ... (rest 3) => n = M₅ + 3 / +2 ... n+2 = M₅
n : 6 = ... (rest 4) si n = M₆ + 4 / +2 ... n+2 = M₆
n : 8 = ... (rest 6) n = M₈ + 6 / +2 ... n+2 = M₈
⇵
n₍minim₎ = M₍₅,₆,₈) = 120 -2 =118
n(maxim) = [(+∞∈N) × 118 = +∞ ∈ N