1)
2-2√6=2 - 2×2,... = minus ceva.
Deci 0 > 2-2√6
2)
[tex] \frac{ \sqrt{2}+1 }{\sqrt{2}-1} = \frac{ (\sqrt{2}+1)^{2}}{ (\sqrt{2}-1)(\sqrt{2}+1)} = \frac{2-2 \sqrt{2}+1 }{2-1} = 3-2 \sqrt{2} \\ \sqrt{8} = 2 \sqrt{2} \\ \\ \Rightarrow 2 \sqrt{2} \square 3- 2 \sqrt{2}|-2 \sqrt{2} \Rightarrow 0\ \textless \ 3- 4 \sqrt{2} \\ \Rightarrow\sqrt{8} \ \textless \ \frac{ \sqrt{2}+1 }{\sqrt{2}-1}[/tex]
