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Ajutor urgent!!!!

calculati media ponderata a numerelor:

[tex] \frac{6}{7} , \frac{9}{8}, \frac{5}{3}, \frac{3}{11} [/tex] cu ponderile 2,(3),2 \frac{2}{3} , 3 si 3,(6)


Răspuns :

[(6/7 * 23-2/9) + 9/8 * 8/3 + 5/3 *3 +(3/11 *36-3/9)] : (21/9+8/3+3+33/9) =
(6/7*21/9 + 3+ 5 +3/11*33/9) : (7/3+8/3+9/3+11/3) =
(2+3+5+1) : 25/3 =
11*3/25=33/25