a -> primul numar
[tex] \frac{3a}{2} [/tex] -> al 2-lea numar
a+ [tex] \frac{3a}{2} [/tex] =68
[tex] \frac{2a+3a}{2} [/tex] =68 | *2
5a=138 => a= [tex] \frac{136}{5} [/tex]
[tex] \frac{408}{10} [/tex] al doilea numar
la verificare iese ca le-am verificat eu
