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Stiind ca a+b+c=13,calculeaza
3a+3b+3c
5a+5b+5c+12
10a+10b+10c-100
11a+11b+11c+309
1000-(25a+25b+25c)
a+(b+c)


Răspuns :

a+b+c=13
________

a) 3a+3b+3c=13*3=39

b) 5a+5b+5c+12= 13*5+12= 65+12= 77

c) 10a+10b+10c-100= 13*10-100= 130-100= 30

d) 11a+11b+11c+309= 13*11+309= 143+309= 452

e) 1000-(25a+25b+25c)= 1000-325= 675

f) a+(b+c)= 13