I2 ====== 2I
I: 1 0
C: x 0
E: 1-x 2x
Nr total de moli amestec la echilibru =1 – x + 2x
= 1 +x
M medie amestec = nI2 ∙MI2/n total
+ nI ∙MI/n total
=(1-x) 254/(1+x) + 2x ∙127/(1+x) = 212 =>x= 0,2 moli
din 1 mol I2 se
descompun..................0.2 moli I2
100 moli
I2....................................w
w=20% de iod disociat