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suma a5 nr este 40.primele 3 numere sunt pare consecutive.ultimele 2 nr sunt impare consecutivesi daca le adunam obtinem 16

Răspuns :

a   /-------------/
b  /-------------/-2-/
c  /-------------/-2-/-2-/
d  /------------/
e /-------------/-2-/
16-2=14
14:2=7
d=7
e=7+2
e=9
40-16=24(suma a+b+c)
24-6=18
18:3=6
a=6
b=6+2
b=8
c=6+4
c=10
V:6+8+10+7+9=40