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Rezolvați in multimea Q plus urmatoarele ex
A) x+5=18,6
B) 21+x=65,4
C) 4,5+x=32,5
D) 9,1+x=99,4
E) x-8=14,2
F) x-12=12,6
Ajutati-ma pls


Răspuns :

A) x+5=18,6
[tex]x= \frac{186}{10} -5= \frac{186-5*2}{10} = \frac{176}{10} [/tex]
B) 21+x=65,4
[tex]x= \frac{654}{10} - 21 = \frac{654-21*10}{10} = \frac{444}{10} [/tex]
C) 4,5+x=32,5
[tex]x= \frac{325}{10} - \frac{45}{10} = \frac{280}{10} [/tex]
D) 9,1+x=99,4
[tex]x= \frac{994}{10} - \frac{91}{10} = \frac{903}{10} [/tex]
E) x-8=14,2
[tex]x= \frac{142}{10} +8= \frac{142+8*10}{10} = \frac{222}{10} [/tex]
F) x-12=12,6
[tex]x= \frac{126}{10} +12= \frac{126+12*10}{10} = \frac{246}{10} [/tex]