a) clorul se obtine prin oxidarea acidului clorhidric cu clorat de potasiu
b) KClO3 + 6HCl --> 3Cl2 + 3H2O + KCl
c) 0.98*2.5=2.45g KClO3 pur
1mol KClO3...6mol HCl...3mol Cl2
2.45mol.......x=14.7mol...y=7.35 moli Cl2
d) 1mol KClO3.......6mol HCl
0.02 mol...............x=0.12mol
n=md/M==>md=n*M=0.12*36.5=4.38g HCl
Cp=md/ms*100==>ms=md*100/Cp=4.38*100/36=12.16g
ro=ms/Vs==>Vs=ms/ro=12.16/1.183=10.284 L