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Calculați: (2x-3)²-(x+2)²+3(x-1)(x+1)-x(3-x).
REZOLVAREA,VĂ ROG!!


Răspuns :

(2x-3)²-(x+2)²+3(x-1)(x+1)-x(3-x)=
=(2x-3-x-2)(
2x-3+x+2)+3(x²-1)-3x+x²=
=(x-5)(3x-1)+3x²-3-3x+x²=
=3x²-15x-x+5+4x²-3-3x=
=7x²-19x+2