[tex]\displaystyle 1) \\
\texttt{Aplicam formulele:} \\
\log_ab + \log_ac = \log_a bc \\
\log_ab - \log_ac = \log_a b/c \\
\log_63 + \log_610 - \log_65 = \log_6 \left(\frac{3\times 10}{5} \right) = \log_6 \left(\frac{30}{5} \right) =\log_66 =1 [/tex]
[tex]\displaystyle 3) \\
(2x+1)^2 = 4 \\
(2x+1)^2 - 4 =0\\
(2x+1)^2 - 2^2 =0\\ \\
(2x+1 + 2)(2x+1-2)=0 \\
(2x+3)(2x-1)=0 \\ \\
2x+3 = 0~~sau~~2x-1=0 \\ \\
x_1 = \boxed{- \frac{3}{2} } \\ \\
x_2 = \boxed{\frac{1}{2} }
[/tex]
