6)
scriem aria tr. ABC in 2 moduri
a) BC x AD = AC x BE
AC=BC x AD/BE = 6 x 5/3
AC=10
b) aceiasi relatie ca la a)
AD=AC x BE/BC = 35 x 16/14
AD=40
c) din aceiasi relatie
BE=BC x AD/AC = ah/b
8)
aria tr. BEC + aria tr. BEA= aria tr ABC- aria tr.CEA
notam DE=x
aria tr ABC=AC(EB+x)/2 = 4(6+x)=24+4x
aria tr. CEA=AC . x/2 = 4x
aria ABC- aria CEA=24+4x - 4x=24 cm2
verifica si tu ca io nu mai am timp