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Aflati 3 numere naturale x,y,z, stiind ca x+y=56 , y+z=88 si x+z=80.

Răspuns :

x+y=56=>x=56-y
y+z=88=>z=88-y
x+z=80=>x=80-z=80-88+y

Egalam,cei,doi,x
56-y=y-8
2y=64=>y=32
x=56-32=>x=24
z=80-24=>z=56
scrie exact cum zic eu
x+y=56
y+z=88
x+z=80
56÷2=28
88-28=60÷2=30
80-28=52÷2= 26
y=30
x=26
z=30sau26