a) HCl masa molara=36,5 g/mol
c=(md/ms)*100
d=ms/Vs
Nr. moli=md/masa molara
C=Nr. moli/Vs
=> C=(md/masa molara)/(ms/d)=(md*d)/(masa molara*ms)=(md/ms)*d/masa molara
=(c/100)*d/masa molara=0,03*1,15/36,5=0,000945=9,45*10^(-4)
=>pH=-lgC=4
pOH=14-pH=10
b) la fel ca la subpuctul a) doar foloseste valorile date