CaHbOcNdXe
C7H14
NE=(2a+2)(b-d+e)/2=(2*7+2)-14/2=16-14/2=2/2=1 leg. dubla
a) CH3-CH=C(CH3)-CH(CH3)-CH3 are un atom de C cuaternar, deci iese din ecuatie
b) CH3-C(CH3)=CH-CH(CH3)-CH3 are un atom de C cuaternar
c) CH3-CH=CH-C(CH3)2-CH3 are un atom de C cuaternar
d) CH3-C(CH3)=C(CH3)-CH2-CH3 are 2 atomi de C cuaternar ===> R:d) este corect