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2a/a+1 + (3/(a-1)^2 - 3/a^2-1)
numarul 1.151 PLEASE


2aa1 3a12 3a21 Numarul 1151 PLEASE class=

Răspuns :

2a/(a+1)+[3(a+1)-3(a-1)]/(a-1)²(a+1)]:3/(a-1)²
2a/(a+1)+[3a+3-3a+3]/(a-1)²(a+1)*(a-1)²/3
2a/(a+1)+2/(a+1)
2(a+1)/(a+1)=2