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Exprima următoarele lungimi in S.I a)L=0.0042Mm b)L=4500 mm c)L=82 hm d)L=0,5 km e)L=0.95 dam f)L=75000 m g)L=5 cm h)L=85 dm i)L=625000000 j)L=4 gm
k)L=0.0052 Tm


Răspuns :

a)L=0.0042Mm=0.0042×[tex] 10^{6} [/tex]=4200m
b)L=4500mm=4500×[tex] 10^{-3} [/tex]=4,5m
c)L=82hm=82×[tex] 10^{2} [/tex]=8200m
d)L=0,5km=0,5×[tex]10^{3} [/tex]=500m
e)L=0.95dam=0,95×10=9,5m
f)L=75000m=75km
g)L=5cm=5×[tex] 10^{-2} [/tex]=0.05m
h)L=85dm=85×[tex] 10^{-1} [/tex]=8.5m
i)L=625000000m=625000000×[tex] 10^{-3} [/tex]=625000km,625×[tex] 10^{6} [/tex]m
j)L=4gm=4×[tex] 10^{9} [/tex]=4000000000m