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Suma a doua nr este31.la impartirea lor se obtine 4r1.aflati nr

Răspuns :

a+b=31
a:b=4r1
a=4b+1
4b+b+1=31
5b+1=31
5b=31-1=30
b=30:5
b=6
a=4x6+1=25
x+y=31
x/y =4  r 1  :  x=4y+1  inlocuim in prima relatie pe  x
4y+1 +y =31
5y =31-1
5y =30
y =6
x=4y+1
x=4*6+1
x=24+1
x=25
( V : 25+6 =31 )